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Angular diameter

How large a sphere or circle appears

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  • 4 chapters
This image is for clearly explaining the concept of angular diameter which is used in astronomy.
Sriram.aeropsn · Public domain

Related on Lably

Through Angle, Sphere and Circle

A person can resolve with their naked eyes diameters down to about 1 arcminute (approximately 0.017° or 0.0003 radians). This corresponds to 0.3 m at a 1 km distance, or to perceiving Venus as a disk under optimal conditions.

Formulation

The angular diameter of a circle whose plane is perpendicular to the displacement vector between the point of view and the center of said circle can be calculated using the formula

δ=2arctan⁡(d2D),

in which δ is the angular diameter (in units of angle, normally radians, sometimes in degrees, depending on the arctangent implementation), d is the linear diameter of the object (in units of length), and D is the distance to the object (also in units of length). When D≫d, we have:

δ≈d/D,

and the result obtained is necessarily in radians.

For a sphere

For a spherical object whose linear diameter equals d and where D is the distance to the center of the sphere, the angular diameter can be found by the following modified formula

δ=2arcsin⁡(d2D)

Such a different formulation is because the apparent edges of a sphere are its tangent points, which are closer to the observer than the center of the sphere, and have a distance between them which is smaller than the actual diameter. The above formula can be found by understanding that in the case of a spherical object, a right triangle can be constructed such that its three vertices are the observer, the center of the sphere, and one of the sphere's tangent points, with D as the hypotenuse and dact2D as the sine.

The formula is related to the zenith angle to the horizon,

δ=π−2arccos⁡(RR+h)

where R is the radius of the sphere and h is the distance to the near surface of the sphere.

The difference with the case of a perpendicular circle is significant only for spherical objects of large angular diameter, since the following small-angle approximations hold for small values of x:

arcsin⁡x≈arctan⁡x≈x.

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