Bell's spaceship paradox

Bell

In Bell's version of the thought experiment, three spaceships A, B and C are initially at rest in a common inertial reference frame, B and C being equidistant to A. Then, a signal is sent from A to reach B and C simultaneously, causing B and C starting to accelerate in the vertical direction (having been pre-programmed with identical acceleration profiles), while A stays at rest in its original reference frame. According to Bell, this implies that B and C (as seen in A's rest frame) "will have at every moment the same velocity, and so remain displaced one from the other by a fixed distance." Now, if a fragile thread is tied between B and C, it's not long enough anymore due to length contractions, thus it will break. He concluded that "the artificial prevention of the natural contraction imposes intolerable stress".

Bell reported that he encountered much skepticism from "a distinguished experimentalist" when he presented the paradox. To attempt to resolve the dispute, an informal and non-systematic survey of opinion at CERN was held. According to Bell, there was "clear consensus" which asserted, incorrectly, that the string would not break. Bell goes on to add,

"Of course, many people who get the wrong answer at first get the right answer on further reflection. Usually they feel obliged to work out how things look to observers B or C. They find that B, for example, sees C drifting further and further behind, so that a given piece of thread can no longer span the distance. It is only after working this out, and perhaps only with a residual feeling of unease, that such people finally accept a conclusion which is perfectly trivial in terms of A's account of things, including the Fitzgerald contraction."

Importance of length contraction

In general, it was concluded by Dewan & Beran and Bell, that relativistic stresses arise when all parts of an object are accelerated the same way with respect to an inertial frame, and that length contraction has real physical consequences. For instance, Bell argued that the length contraction of objects as well as the lack of length contraction between objects in frame S can be explained using relativistic electromagnetism. The distorted electromagnetic intermolecular fields cause moving objects to contract, or to become stressed if hindered from doing so. In contrast, no such forces act on the space between objects. (Generally, Richard Feynman demonstrated how the Lorentz transformation can be derived from the case of the potential of a charge moving with constant velocity (as represented by the Liénard–Wiechert potential). As to the historical aspect, Feynman alluded to the circumstance that Hendrik Lorentz arrived essentially the same way at the Lorentz transformation, see also History of Lorentz transformations.)

However, Petkov (2009) and Franklin (2009) interpret this paradox differently. They agreed with the result that the string will break due to unequal accelerations in the rocket frames, which causes the rest length between them to increase (see the Minkowski diagram in the analysis section). However, they denied the idea that those stresses are caused by length contraction in S. This is because, in their opinion, length contraction has no "physical reality", but is merely the result of a Lorentz transformation, i.e. a rotation in four-dimensional space which by itself can never cause any stress at all. Thus the occurrence of such stresses in all reference frames including S and the breaking of the string is supposed to be the effect of relativistic acceleration alone.

Analysis

Paul Nawrocki (1962) gives three arguments why the string should not break, while Edmond Dewan (1963) showed in a reply that his original analysis still remains valid. Many years later and after Bell's book, Matsuda and Kinoshita reported receiving much criticism after publishing an article on their independently rediscovered version of the paradox in a Japanese journal. Matsuda and Kinoshita do not cite specific papers, however, stating only that these objections were written in Japanese.

However, in most publications it is agreed that the string will break, with some reformulations, modifications and different scenarios, such as by Evett & Wangsness (1960), Dewan (1963), Romain (1963), Evett (1972), Gershtein & Logunov (1998), Tartaglia & Ruggiero (2003), Cornwell (2005), Flores (2005), Semay (2006), Styer (2007), Freund (2008), Redzic (2008), Peregoudov (2009), Redžić (2009), Gu (2009), Petkov (2009), Franklin (2009), Miller (2010), Fernflores (2011), Kassner (2012), Natario (2014), Lewis, Barnes & Sticka (2018), Bokor (2018). A similar problem was also discussed in relation to angular accelerations: Grøn (1979), MacGregor (1981), Grøn (1982, 2003).

Immediate acceleration

Similarly, in the case of Bell's spaceship paradox the relation between the initial rest length ${\displaystyle L}$ between the ships (identical to the moving length in S after acceleration) and the new rest length ${\displaystyle L^{\prime }}$ in S′ after acceleration, is:

${\displaystyle L^{\prime }=\gamma L}$.

This length increase can be calculated in different ways. For instance, if the acceleration is finished the ships will constantly remain at the same location in the final rest frame S′, so it's only necessary to compute the distance between the x-coordinates transformed from S to S′. If ${\displaystyle x_A}$ and ${\displaystyle x_B=x_A+L}$ are the ships' positions in S, the positions in their new rest frame S′ are:

${\displaystyle \begin{array}{cc}{x}_A^{\prime }& =\gamma \left(x_A-vt\right)\\ x_B^{\prime }& =\gamma \left(x_A+L-vt\right)\\ L^{\prime }& =x_B^{\prime }-x_A^{\prime }\\ & =\gamma L\end{array}}$

Another method was shown by Dewan (1963) who demonstrated the importance of relativity of simultaneity. The perspective of frame S′ is described, in which both ships will be at rest after the acceleration is finished. The ships are accelerating simultaneously at ${\displaystyle t_A=t_B}$ in S (assuming acceleration in infinitesimal small time), though B is accelerating and stopping in S′ before A due to relativity of simultaneity, with the time difference:

${\displaystyle \begin{array}{cc}\mathrm{\Delta }{t}^{\prime }& =t_B^{\prime }-t_A^{\prime }=\gamma \left(t_B-\frac{v{x}_B}{c^2}\right)-\gamma \left(t_A-\frac{v{x}_A}{c^2}\right)\\ & =\frac{\gamma vL}{c^2}\end{array}}$

Since the ships are moving with the same velocity in S′ before acceleration, the initial rest length ${\displaystyle L}$ in S is shortened in S′ by ${\displaystyle L_{old}^{\prime }=L/\gamma }$ due to length contraction. From the frame of S′, B starts accelerating before A and also stops accelerating before A. Due to this B will always have higher velocity than A up until the moment A is finished accelerating too, and both of them are at rest with respect to S′. The distance between B and A keeps on increasing till A stops accelerating. Although A's acceleration timeline is delayed by an offset of ${\displaystyle \mathrm{\Delta }{t}^{\prime }}$, both A and B cover the same distance in their respective accelerations. But B's timeline contains acceleration and also being at rest in S` for ${\displaystyle \mathrm{\Delta }{t}^{\prime }}$ till A stops accelerating. Hence the extra distance covered by B during the entire course can be calculated by measuring the distance traveled by B during this phase. Dewan arrived at the relation (in different notation):

${\displaystyle \begin{array}{cc}{L}^{\prime }& =L_{old}^{\prime }+v\mathrm{\Delta }{t}^{\prime }=\frac{L}{\gamma }+\frac{\gamma v^{2}L}{c^2}\\ & =\gamma L\end{array}}$

It was also noted by several authors that the constant length in S and the increased length in S′ is consistent with the length contraction formula ${\displaystyle L=L^{\prime }/\gamma }$, because the initial rest length ${\displaystyle L}$ is increased by ${\displaystyle \gamma }$ in S′, which is contracted in S by the same factor, so it stays the same in S:

${\displaystyle L_{contr.}=L^{\prime }/\gamma =\gamma L/\gamma =L}$

Summarizing: While the rest distance between the ships increases to ${\displaystyle \gamma L}$ in S′, the relativity principle requires that the string (whose physical constitution is unaltered) maintains its rest length ${\displaystyle L}$ in its new rest system S′. Therefore, it breaks in S′ due to the increasing distance between the ships. As explained above, the same is also obtained by only considering the start frame S using length contraction of the string (or the contraction of its moving molecular fields) while the distance between the ships stays the same due to equal acceleration.

Constant proper acceleration

Instead of instantaneous changes of direction, special relativity also allows to describe the more realistic scenario of constant proper acceleration, i.e. the acceleration indicated by a comoving accelerometer. This leads to hyperbolic motion, in which the observer continuously changes momentary inertial frames

${\displaystyle \begin{array}{cc}x& =\frac{c^2}{\alpha }\left(\sqrt{1+{\left(\frac{\alpha t}{c}\right)}^2}-1\right)=\frac{c^2}{\alpha }\left(\cosh \frac{\alpha \tau }{c}-1\right)\\ c\tau & =\frac{c^2}{\alpha }\mathrm{asinh}\frac{\alpha t}{c},ct=\frac{c^2}{\alpha }\sinh \frac{\alpha \tau }{c}\end{array}}$

where ${\displaystyle t}$ is the coordinate time in the external inertial frame, and ${\displaystyle \tau }$ the proper time in the momentary frame, and the momentary velocity is given by

${\displaystyle v=\frac{\alpha t}{\sqrt{1+{\left(\frac{\alpha t}{c}\right)}^2}}=c\tanh \frac{\alpha \tau }{c}}$

The mathematical treatment of this paradox is similar to the treatment of Born rigid motion. However, rather than ask about the separation of spaceships with the same acceleration in an inertial frame, the problem of Born rigid motion asks, "What acceleration profile is required by the second spaceship so that the distance between the spaceships remains constant in their proper frame?" In order for the two spaceships, initially at rest in an inertial frame, to maintain a constant proper distance, the lead spaceship must have a lower proper acceleration.

This Born rigid frame can be described by using Rindler coordinates (Kottler-Møller coordinates)

${\displaystyle \begin{array}{cccc}ct& =\left(x^{\prime }+\frac{c^2}{\alpha }\right)\sinh \frac{\alpha t^{\prime }}{c},& y& =y^{\prime },\\ x& =\left(x^{\prime }+\frac{c^2}{\alpha }\right)\cosh \frac{\alpha t^{\prime }}{c}-\frac{c^2}{\alpha },& z& =z^{\prime }.\end{array}(t^{\prime }=\tau )}$

The condition of Born rigidity requires that the proper acceleration of the spaceships differs by

${\displaystyle {\alpha }_2=\frac{{\alpha }_1}{1+\frac{{\alpha }_1{L}^{\prime }}{c^2}}}$

and the length ${\displaystyle L^{\prime }=x_2^{\mathrm{\prime }}-x_1^{\mathrm{\prime }}}$ measured in the Rindler frame (or momentary inertial frame) by one of the observers is Lorentz contracted to ${\displaystyle L=x_2-x_1}$ in the external inertial frame by

${\displaystyle L=\frac{L^{\prime }}{\cosh \frac{\alpha t^{\prime }}{c}}=L^{\prime }\sqrt{1-\frac{v^2}{c^2}}}$

which is the same result as above. Consequently, in the case of Born rigidity, the constancy of length L' in the momentary frame implies that L in the external frame decreases constantly, the thread doesn't break. However, in the case of Bell's spaceship paradox the condition of Born rigidity is broken, because the constancy of length L in the external frame implies that L' in the momentary frame increases, the thread breaks (in addition, the expression for the distance increase between two observers having the same proper acceleration becomes also more complicated in the momentary frame).