Binomial heap

Structure of a binomial heap

A binomial heap is implemented as a set of binomial trees that satisfy the binomial heap properties:

• Each binomial tree in a heap obeys the minimum-heap property: the key of a node is greater than or equal to the key of its parent.
• There can be at most one binomial tree for each order, including zero order.

The first property ensures that the root of each binomial tree contains the smallest key in the tree. It follows that the smallest key in the entire heap is one of the roots.

The second property implies that a binomial heap with ${\displaystyle n}$ nodes consists of at most ${\displaystyle 1+{\log }_{2}n}$ binomial trees, where ${\displaystyle {\log }_2}$ is the binary logarithm. The number and orders of these trees are uniquely determined by the number of nodes ${\displaystyle n}$: there is one binomial tree for each nonzero bit in the binary representation of the number ${\displaystyle n}$. For example, the decimal number 13 is 1101 in binary, ${\displaystyle 2^3+2^2+2^0}$, and thus a binomial heap with 13 nodes will consist of three binomial trees of orders 3, 2, and 0 (see figure below).

The number of different ways that ${\displaystyle n}$ items with distinct keys can be arranged into a binomial heap equals the largest odd divisor of ${\displaystyle n!}$. For ${\displaystyle n=1,2,3,\dots }$ these numbers are

1, 1, 3, 3, 15, 45, 315, 315, 2835, 14175, ... (sequence A049606 in the OEIS)

If the ${\displaystyle n}$ items are inserted into a binomial heap in a uniformly random order, each of these arrangements is equally likely.

Implementation

Because no operation requires random access to the root nodes of the binomial trees, the roots of the binomial trees can be stored in a linked list, ordered by increasing order of the tree. Because the number of children for each node is variable, it does not work well for each node to have separate links to each of its children, as would be common in a binary tree; instead, it is possible to implement this tree using links from each node to its highest-order child in the tree, and to its sibling of the next smaller order than it. These sibling pointers can be interpreted as the next pointers in a linked list of the children of each node, but with the opposite order from the linked list of roots: from largest to smallest order, rather than vice versa. This representation allows two trees of the same order to be linked together, making a tree of the next larger order, in constant time.

Merge

The operation of merging two heaps is used as a subroutine in most other operations. A basic subroutine within this procedure merges pairs of binomial trees of the same order. This may be done by comparing the keys at the roots of the two trees (the smallest keys in both trees). The root node with the larger key is made into a child of the root node with the smaller key, increasing its order by one:

<b id="mwlw">function</b> mergeTree(p, q) <b id="mwmA">if</b> p.root.key <= q.root.key <b id="mwmQ">return</b> p.addSubTree(q) <b id="mwmg">else</b> <b id="mwmw">return</b> q.addSubTree(p)

To merge two heaps more generally, the lists of roots of both heaps are traversed simultaneously in a manner similar to that of the merge algorithm, in a sequence from smaller orders of trees to larger orders. When only one of the two heaps being merged contains a tree of order ${\displaystyle j}$, this tree is moved to the output heap. When both of the two heaps contain a tree of order ${\displaystyle j}$, the two trees are merged to one tree of order ${\displaystyle j+1}$ so that the minimum-heap property is satisfied. It may later become necessary to merge this tree with some other tree of order ${\displaystyle j+1}$ in one of the two input heaps. In the course of the algorithm, it will examine at most three trees of any order, two from the two heaps we merge and one composed of two smaller trees.

<b id="mwrw">function</b> merge(p, q) <b id="mwsA">while</b> <b id="mwsQ">not</b> (p.end() <b id="mwsg">and</b> q.end()) tree = mergeTree(p.currentTree(), q.currentTree())

<b id="mwtA">if</b> <b id="mwtQ">not</b> heap.currentTree().empty() tree = mergeTree(tree, heap.currentTree())

heap.addTree(tree) heap.next(); p.next(); q.next()

Because each binomial tree in a binomial heap corresponds to a bit in the binary representation of its size, there is an analogy between the merging of two heaps and the binary addition of the sizes of the two heaps, from right-to-left. Whenever a carry occurs during addition, this corresponds to a merging of two binomial trees during the merge.

Each binomial tree's traversal during merge only involves roots, hence making the time taken at most order ${\displaystyle {\log }_{2}n}$ and therefore the running time is ${\displaystyle O(\log n)}$.

Insert

Inserting a new element to a heap can be done by simply creating a new heap containing only this element and then merging it with the original heap. Because of the merge, a single insertion takes time ${\displaystyle O(\log n)}$. However, this can be sped up using a merge procedure that shortcuts the merge after it reaches a point where only one of the merged heaps has trees of larger order. With this speedup, across a series of ${\displaystyle k}$ consecutive insertions, the total time for the insertions is ${\displaystyle O(k+\log n)}$. Another way of stating this is that (after logarithmic overhead for the first insertion in a sequence) each successive insert has an amortized time of ${\displaystyle O(1)}$ (i.e. constant) per insertion.

A variant of the binomial heap, the skew binomial heap, achieves constant worst case insertion time by using forests whose tree sizes are based on the skew binary number system rather than on the binary number system.

Find minimum

To find the minimum element of the heap, find the minimum among the roots of the binomial trees. This can be done in ${\displaystyle O(\log n)}$ time, as there are just ${\displaystyle O(\log n)}$ tree roots to examine.

By using a pointer to the binomial tree that contains the minimum element, the time for this operation can be reduced to ${\displaystyle O(1)}$. The pointer must be updated when performing any operation other than finding the minimum. This can be done in ${\displaystyle O(\log n)}$ time per update, without raising the overall asymptotic running time of any operation.

Delete minimum

To delete the minimum element from the heap, first find this element, remove it from the root of its binomial tree, and obtain a list of its child subtrees (which are each themselves binomial trees, of distinct orders). Transform this list of subtrees into a separate binomial heap by reordering them from smallest to largest order. Then merge this heap with the original heap. Since each root has at most ${\displaystyle {\log }_{2}n}$ children, creating this new heap takes time ${\displaystyle O(\log n)}$. Merging heaps takes time ${\displaystyle O(\log n)}$, so the entire delete minimum operation takes time ${\displaystyle O(\log n)}$.

<b id="mw_w">function</b> deleteMin(heap) min = heap.trees().first() <b id="mwAQA">for each</b> current <b id="mwAQE">in</b> heap.trees() <b id="mwAQI">if</b> current.root < min.root <b id="mwAQM">then</b> min = current <b id="mwAQQ">for each</b> tree <b id="mwAQU">in</b> min.subTrees() tmp.addTree(tree) heap.removeTree(min) merge(heap, tmp)

Decrease key

After decreasing the key of an element, it may become smaller than the key of its parent, violating the minimum-heap property. If this is the case, exchange the element with its parent, and possibly also with its grandparent, and so on, until the minimum-heap property is no longer violated. Each binomial tree has height at most ${\displaystyle {\log }_{2}n}$, so this takes ${\displaystyle O(\log n)}$ time. However, this operation requires that the representation of the tree include pointers from each node to its parent in the tree, somewhat complicating the implementation of other operations.

Delete

To delete an element from the heap, decrease its key to negative infinity (or equivalently, to some value lower than any element in the heap) and then delete the minimum in the heap.

Summary of running times

Here are time complexities of various heap data structures. The abbreviation am. indicates that the given complexity is amortized, otherwise it is a worst-case complexity. For the meaning of "O(f)" and "Θ(f)" see Big O notation. Names of operations assume a min-heap.

Applications

• Discrete event simulation
• Priority queues