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Bisection

Division of something into two equal or congruent parts

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Perpendicular line segment bisector

Definition

  • The perpendicular bisector of a line segment is a line which meets the line segment at its midpoint perpendicularly.
  • The perpendicular bisector of a line segment AB also has the property that each of its points X is equidistant from the endpoints of line segment AB:

(D)|XA|=|XB|.

The proof follows from |MA|=|MB| and Pythagoras' theorem:

|XA|2=|XM|2+|MA|2=|XM|2+|MB|2=|XB|2.

Property (D) is usually used for the construction of a perpendicular bisector:

Construction by straightedge and compass

In classical geometry, bisection is a simple straightedge and (collapsible) compass construction as per Proposition 10 in Book 1 of Euclid's Elements. This method served his purposes for writing deductive and logical proofs. Today, a ruler and (non-collapsible) compass can be used to draw the perpendicular bisector of a line segment.

The line segment AB is bisected by drawing two intersecting circles of equal radius r>12|AB|, whose centers are the endpoints of the line segment. The line determined by the two points of intersection of the circles (points X1and X2) is the perpendicular bisector of the line segment. The point at which the bisector intersects the line segment determines the midpoint M of the line segment.

This construction is in fact used when constructing a line perpendicular to a given line g at a given point P: drawing a circle whose center is P such that it intersects the line g in two points A,B, and the perpendicular to be constructed is the one bisecting line segment AB.

Equations

If a→,b→ are the position vectors of two points A,B, then its midpoint is M:m→=a→+b→2 and vector a→−b→ is a normal vector of the perpendicular line segment bisector. Hence its vector equation is (x→−m→)⋅(a→−b→)=0. Inserting m→=⋯ and expanding the equation leads to the vector equation

(V) x→⋅(a→−b→)=12(a→2−b→2).

With A=(a1,a2),B=(b1,b2) one gets the equation in coordinate form:

(C) (a1−b1)x+(a2−b2)y=12(a12−b12+a22−b22).

Or explicitly:
(E)y=m(x−x0)+y0,
where m=−b1−a1b2−a2, x0=12(a1+b1), and y0=12(a2+b2).

Applications

Perpendicular line segment bisectors were used to solve various geometric problems:

  1. Construction of the center of a Thales' circle,
  2. Construction of the center of the Excircle of a triangle,
  3. Voronoi diagram boundaries consist of segments of such lines or planes.

Perpendicular line segment bisectors in space

  • The perpendicular bisector of a line segment is a plane, which meets the line segment at its midpoint perpendicularly.

Its vector equation is literally the same as in the plane case:

(V) x→⋅(a→−b→)=12(a→2−b→2).

With A=(a1,a2,a3),B=(b1,b2,b3) one gets the equation in coordinate form:

(C3) (a1−b1)x+(a2−b2)y+(a3−b3)z=12(a12−b12+a22−b22+a32−b32).

Property (D) (see above) is literally true in space, too:
(D) The perpendicular bisector plane of a line segment AB has for any point X the property: |XA|=|XB|.

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