Chain (algebraic topology)

Integration on chains

Integration is defined on chains by taking the linear combination of integrals over the simplices in the chain with coefficients (which are typically integers). The set of all k-chains forms a group and the sequence of these groups is called a chain complex.

Boundary operator on chains

The boundary of a chain is the linear combination of boundaries of the simplices in the chain. The boundary of a k-chain is a (k−1)-chain. Note that the boundary of a simplex is not a simplex, but a chain with coefficients 1 or −1 – thus chains are the closure of simplices under the boundary operator.

Example 1: The boundary of a path is the formal difference of its endpoints: it is a telescoping sum. To illustrate, if the 1-chain ${\displaystyle c=t_1+t_2+t_3}$ is a path from point ${\displaystyle v_1}$ to point ${\displaystyle v_4}$, where ${\displaystyle t_1=[v_1,v_2]}$, ${\displaystyle t_2=[v_2,v_3]}$ and ${\displaystyle t_3=[v_3,v_4]}$ are its constituent 1-simplices, then

${\displaystyle \begin{array}{cc}{\mathrm{\partial }}_{1}c& ={\mathrm{\partial }}_1(t_1+t_2+t_3)\\ & ={\mathrm{\partial }}_1(t_1)+{\mathrm{\partial }}_1(t_2)+{\mathrm{\partial }}_1(t_3)\\ & ={\mathrm{\partial }}_1([v_1,v_2])+{\mathrm{\partial }}_1([v_2,v_3])+{\mathrm{\partial }}_1([v_3,v_4])\\ & =([v_2]-[v_1])+([v_3]-[v_2])+([v_4]-[v_3])\\ & =[v_4]-[v_1].\end{array}}$

Example 2: The boundary of the triangle is a formal sum of its edges with signs arranged to make the traversal of the boundary counterclockwise.

A chain is called a cycle when its boundary is zero. A chain that is the boundary of another chain is called a boundary. Boundaries are cycles, so chains form a chain complex, whose homology groups (cycles modulo boundaries) are called simplicial homology groups.

Example 3: The plane punctured at the origin has nontrivial 1-homology group since the unit circle is a cycle, but not a boundary.

In differential geometry, the duality between the boundary operator on chains and the exterior derivative is expressed by the general Stokes' theorem.