Lably
Skip to content

Duhem–Margules equation

  • 1 min read
  • 1 chapter

Related on Lably

Through Thermodynamics, Component (thermodynamics) and Liquid

(dln⁡PAdln⁡xA)T,P=(dln⁡PBdln⁡xB)T,P

where PA and PB are the partial vapour pressures of the two constituents and xA and xB are the mole fractions of the liquid. The equation gives the relation between changes in mole fraction and partial pressure of the components.

Derivation

Let us consider a binary liquid mixture of two component in equilibrium with their vapor at constant temperature and pressure. Then from the Gibbs–Duhem equation, we have

Where nA and nB are number of moles of the component A and B while μA and μB are their chemical potentials.

Dividing equation (1) by nA + nB, then

nAnA+nBdμA+nBnA+nBdμB=0

Or

Now the chemical potential of any component in mixture is dependent upon temperature, pressure and the composition of the mixture. Hence if temperature and pressure are taken to be constant, the chemical potentials must satisfy

Putting these values in equation (2), then

Because the sum of mole fractions of all components in the mixture is unity, i.e.,

x1+x2=1

we have

dx1+dx2=0

so equation (5) can be re-written:

Now the chemical potential of any component in mixture is such that

μ=μ0+RTln⁡P

where P is the partial pressure of that component. By differentiating this equation with respect to the mole fraction of a component:

dμdx=RTdln⁡Pdx

we have for components A and B

Substituting these value in equation (6), then

xAdln⁡PAdxA=xBdln⁡PBdxB

or

(dln⁡PAdln⁡xA)T,P=(dln⁡PBdln⁡xB)T,P

This final equation is the Duhem–Margules equation.

More in Physics