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Epicyclic gearing

Three-shaft planetary gearset

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  • 13 chapters

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Through Gear, Differential (mechanical device) and Clockwise

An epicyclic gear train can be assembled so that the planet gear rolls on the inside of the pitch circle of an outer gear ring, or ring gear, sometimes called an annulus gear. Such an assembly of a planet engaging both a sun gear and a ring gear is called a planetary gear train. By choosing to hold one component or another—the planetary carrier, the ring gear, or the sun gear—stationary, three different gear ratios can be realized.

One important property of planetary gear systems is their ability to combine multiple rotational inputs into a single output. This behavior can be understood through an equivalent linear (rack-and-pinion) analogy, which simplifies the kinematic relationships.

  • Object A → upper rack corresponds to one gear element (e.g., sun gear)
  • Object C → lower rack corresponds to another gear element (e.g., ring gear)
  • Object B → represents the planet carrier

If Object A is fixed and Object B moves one inch, Object C moves two inches.

C moves twice as far as B, because rotation and translation combine.

Kinematic equations

A simple planetary gear train can be analyzed using an equivalent linear rack-and-pinion model. In this analogy, rack A corresponds to one gear element, such as the sun gear; rack C corresponds to another gear element, such as the ring gear; and body B represents the planet carrier.

Let

vA be the velocity of rack A,
vB be the velocity of carrier B,
vC be the velocity of rack C,
ω be the angular velocity of the planet gear, and
R be the pitch radius of the planet gear.

If rack A is fixed, the no-slip condition at the upper contact point is:

vA=vB−ωR=0.

Therefore,

ωR=vB.

At the lower contact point, the velocity of rack C is the sum of the carrier translation and the rotational contribution of the planet gear:

vC=vB+ωR.

Substituting ωR=vB gives

vC=2vB.

Thus, if carrier B moves one unit while rack A is fixed, rack C moves two units.

More generally, the no-slip conditions at the two contact points are

vA=vB−ωR

and

vC=vB+ωR.

Adding these equations gives

vA+vC=2vB,

or

vB=vA+vC2.

For a planetary gear train, the corresponding rotational quantities are as follows: vA corresponds to Nsωs for the sun gear, vC corresponds to Nrωr for the ring gear, and vB corresponds to (Ns+Nr)ωc for the carrier. Here, Ns is the number of teeth on the sun gear, Nr is the number of teeth on the ring gear, and ωs, ωr, and ωc are the angular velocities of the sun gear, ring gear, and carrier, respectively.

Substituting these quantities gives the standard kinematic relationship

Nsωs+Nrωr=(Ns+Nr)ωc.

This equation describes how the angular velocities of two gear elements determine the angular velocity of the third. If only one element is driven and the others are unconstrained, the motion is not uniquely determined. A fixed member, load condition, or directional constraint, such as a ratchet or one-way clutch, is needed to define a unique output motion. Without a ratchet mechanism, the higher torque input may influence the lower-torque input, resulting in unintended reverse motion or energy transfer.

For example, let

Ns=60,Nr=100,ωs=+0.5,ωc=−0.25.

Solving for the ring gear speed,

60(0.5)+100ωr=(60+100)(−0.25),

so

30+100ωr=−40,
100ωr=−70,

and

ωr=−0.7.

The ring gear therefore rotates with an angular velocity of −0.7, indicating rotation in the negative direction under the chosen sign convention.

A related relationship applies to a symmetric differential, where the carrier speed is the average of the two side-gear speeds:

ωc=ωL+ωR2.

Solving for the right-side gear gives

ωR=2ωc−ωL.

For example, if

ωL=0.5

and

ωc=−0.25,

then

ωR=2(−0.25)−0.5=−1.0.

Modified planetary gear systems have also been proposed for wave-energy applications, where they may help convert irregular, low-speed, pulsating motion into steadier one-directional rotation.

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