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Epimorphism

Surjective homomorphism

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Some authors use the adjective epi (an epimorphism is a morphism which is epi). Epimorphisms are categorical analogues of onto or surjective functions (and in the category of sets the concept corresponds exactly to the surjective functions), but they may not exactly coincide in all contexts. The dual of an epimorphism is a monomorphism (i.e. an epimorphism in a category C is a monomorphism in the dual category Cop).

Epimorphism can be a subtly weaker condition than surjectivity. For example, in the category of rings, the inclusion Z→Q of integers into rational numbers is an epimorphism, since the images of integers under a homomorphism also determine the images of quotients of integers. In the category of Hausdorff spaces, an epimorphism is precisely a continuous function with dense image, since the image of a Cauchy sequence determines the image of its limit point: for example the inclusion Q→R of the metric space of rational numbers into the real number line.

Many authors in abstract algebra and universal algebra define an epimorphism simply as an onto or surjective homomorphism. Every epimorphism in this algebraic sense is an epimorphism in the sense of category theory, but the converse is not true in all categories. In this article, the term "epimorphism" will be used in the sense of category theory given above. For more on this, see § Terminology below.

Examples

In a concrete category (in which each object has an underlying set), if the underlying function of a morphism is surjective, then the morphism is epi. In many concrete categories of interest the converse is also true. For example, in the following categories, the epimorphisms are exactly those morphisms that are surjective on the underlying sets:

  • Set: sets and functions. To prove that every epimorphism f : X → Y in Set is surjective, we compose it with both the characteristic function g1 : Y → {0, 1} of the image f(X) and the map g2 : Y → {0, 1} that is constant 1.
  • Rel: sets with binary relations and relation-preserving functions. Here we can use the same proof as for Set, equipping {0, 1} with the full relation {0, 1}×{0, 1}.
  • Pos: partially ordered sets and monotone functions. If f : (X, ≤) → (Y, ≤) is not surjective, pick y0 in Y \ f(X) and let g1 : Y → {0, 1} be the characteristic function of {y | y0 ≤ y} and g2 : Y → {0, 1} the characteristic function of {y | y0 < y}. These maps are monotone if {0, 1} is given the standard ordering 0 < 1.
  • Grp: groups and group homomorphisms. The result that every epimorphism in Grp is surjective is due to Otto Schreier (he actually proved more, showing that every subgroup is an equalizer using the free product with one amalgamated subgroup); an elementary proof can be found in (Linderholm 1970).
  • FinGrp: finite groups and group homomorphisms. Also due to Schreier; the proof given in (Linderholm 1970) establishes this case as well.
  • Ab: abelian groups and group homomorphisms.
  • K-Vect: vector spaces over a field K and K-linear transformations.
  • Mod-R: right modules over a ring R and module homomorphisms. This generalizes the two previous examples; to prove that every epimorphism f : X → Y in Mod-R is surjective, we compose it with both the canonical quotient map g1 : Y → Y/f(X) and the zero map g2 : Y → Y/f(X).
  • Top: topological spaces and continuous functions. To prove that every epimorphism in Top is surjective, we proceed exactly as in Set, giving {0, 1} the indiscrete topology, which ensures that all considered maps are continuous.
  • HComp: compact Hausdorff spaces and continuous functions. If f : X → Y is not surjective, let y ∈ Y − fX. Since fX is closed, by Urysohn's Lemma there is a continuous function g1 : Y → [0, 1] such that g1 is 0 on fX and 1 on y. We compose f with both g1 and the zero function g2 : Y → [0, 1].

However, there are also many concrete categories of interest where epimorphisms fail to be surjective. A few examples are:

  • In the category of monoids, Mon, the inclusion map N → Z is a non-surjective epimorphism. To see this, suppose that g1 and g2 are two distinct maps from Z to some monoid M. Then for some n in Z, g1(n) ≠ g2(n), so g1(−n) ≠ g2(−n). Either n or −n is in N, so the restrictions of g1 and g2 to N are unequal.
  • In the category of algebras over commutative ring R, take R[x]→R[x,x−1] the polyomials over R included in the Laurent polynomials (this is the morphism of monoid rings corresponding to the above inclusion N → Z). This is an epimorphism since any homomorphism of algebras respects multiplicative inverse whenever it is defined, so the image of x∈R[x] determines the image of any Laurent polynomial.
  • In the category of rings, Ring, the inclusion map Z → Q is a non-surjective epimorphism; to see this, note that any ring homomorphism on Q is determined entirely by its action on Z, similar to the previous example. A similar argument shows that the natural ring homomorphism from any commutative ring R to any one of its localizations is an epimorphism.
  • In the category of commutative rings, a finitely generated homomorphism of rings f : R → S is an epimorphism if and only if for all prime ideals P of R, the ideal Q generated by f(P) is either S or is prime, and if Q is not S, the induced map Frac(R/P) → Frac(S/Q) is an isomorphism (EGA IV 17.2.6).
  • In the category of Hausdorff spaces, Haus, the epimorphisms are precisely the continuous functions with dense images. For example, the inclusion map Q → R is a non-surjective epimorphism.

The above differs from the case of monomorphisms where it is more frequently true that monomorphisms are precisely those whose underlying functions are injective.

As for examples of epimorphisms in non-concrete categories:

  • If a monoid or ring is considered as a category with a single object (composition of morphisms given by multiplication), then the epimorphisms are precisely the right-cancellable elements.
  • If a directed graph is considered as a category (objects are the vertices, morphisms are the paths, composition of morphisms is the concatenation of paths), then every morphism is an epimorphism.

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