Lably
Skip to content

Iodine clock reaction

Experiment to show chemical kinetics in action

  • 4 min read
  • 4 chapters

Related on Lably

Through Chemical kinetics, Iodine and Redox

Hydrogen peroxide variation

This method commences with a solution of hydrogen peroxide and sulfuric acid. To this, a solution containing potassium iodide, sodium thiosulfate, and starch is added. There are two reactions occurring simultaneously in the solution.

In the first, slow reaction, iodine is produced:

H2O2 + 2 I− + 2 H+ → I2 + 2 H2O

In the second, fast reaction, iodine is reconverted to two iodide ions by the thiosulfate:

2 S2O32– + I2 → S4O62– + 2 I−

After some time the solution changes color to a very dark blue, almost black.

H2O2 and I− are both first order. H+ is more complicated.

When the solutions are mixed, the second reaction causes the iodine to be consumed much faster than it is generated, and only a small amount of iodine is present in the dynamic equilibrium. Once the thiosulfate ion has been exhausted, this reaction stops and the blue colour caused by the iodine – starch complex appears.

Anything that accelerates the first reaction will shorten the time until the solution changes color. Decreasing the pH (increasing H+
concentration), or increasing the concentration of iodide or hydrogen peroxide will shorten the time. Adding more thiosulfate will have the opposite effect; it will take longer for the blue colour to appear.

Aside from using sodium thiosulfate as a substrate, cysteine can also be used.

Iodide from potassium iodide is converted to iodine in the first reaction:

2 I− + 2 H+ + H2O2 → I2 + 2 H2O

The iodine produced in the first reaction is reduced back to iodide by the reducing agent, cysteine. At the same time, cysteine is oxidized into cystine.

2 C3H7NO2S + I2 → C6H12N2O4S2 + 2 I− + 2 H+

Similar to the thiosulfate case, the blue color appears when the cysteine is exhausted.

Sign in to keep reading

3 more chapters are free with a Lably account.

More in Chemistry