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Octet rule

Chemical rule of thumb

  • 10 min read
  • 6 chapters
  • 2 labs on Lably
A Lewis structure of carbon dioxide, CO 2 . Structure drawn in ChemBioDraw Ultra 12.0 .
Ben Mills · Public domain

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The valence electrons in molecules like carbon dioxide (CO2) can be visualized using a Lewis electron dot diagram. In covalent bonds, electrons shared between two atoms are counted toward the octet of both atoms. In carbon dioxide each oxygen shares four electrons with the central carbon, two (shown in red) from the oxygen itself and two (shown in black) from the carbon. All four of these electrons are counted in both the carbon octet and the oxygen octet, so that both atoms are considered to obey the octet rule.

Example: sodium chloride (NaCl)

The octet rule is simplest in the case of ionic bonding between two atoms, one a metal of low electronegativity and the other a nonmetal of high electronegativity. For example, sodium metal and chlorine gas combine to form sodium chloride, a crystal lattice composed of alternating sodium and chlorine nuclei. Electron density inside this lattice forms clumps at the atomic scale, as follows.

An isolated chlorine atom (Cl) has two and eight electrons in its first and second electron shells, located near the nucleus. However, it has only seven electrons in the third and outermost electron shell. One additional electron would completely fill the outer electron shell with eight electrons, a situation the octet rule commends. Indeed, adding an electron to the produce the chloride ion (Cl−) releases 3.62 eV of energy. Conversely, another surplus electron cannot fit in the same shell, instead beginning the fourth electron shell around the nucleus. Thus the octet rule proscribes formation of a hypothetical Cl2− ion, and indeed the latter has only been observed as a plasma under extreme conditions.

A sodium atom (Na) has a single electron in its outermost electron shell, the first and second shells again being full with two and eight electrons respectively. The octet rule favors removal of this outermost electron to form the Na+ ion, which has the exact same electron configuration as Cl−. Indeed, sodium is observed to transfer one electron to chlorine during the formation of sodium chloride, such that the resulting lattice is best considered as a periodic array of Na+ and Cl− ions.

To remove the outermost Na electron and return to an "octet-approved" state requires a small amount of energy: 5.14 eV. This energy is provided from the 3.62 eV released during chloride formation, and the electrostatic attraction between positively-charged Na+ and negatively-charged Cl− ions, which releases a 8.12 eV lattice energy. By contrast, any further electrons removed from Na would reside in the deeper second electron shell, and produce an octet-violating Na2+ ion. Consequently, the second ionization energy required for the next removal is much larger – 47.28 eV – and the corresponding ion is only observed under extreme conditions.

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