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Plumbing (mathematics)

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Definition

Let ξi=(Ei,Mi,pi) be a rank n vector bundle over an n-dimensional smooth manifold Mi for i = 1,2. Denote by D(Ei) the total space of the associated (closed) disk bundle D(ξi)and suppose that ξi,Mi and D(Ei)are oriented in a compatible way. If we pick two points xi∈Mi, i = 1,2, and consider a ball neighbourhood of xi in Mi, then we get neighbourhoods Din×Din of the fibre over xi in D(Ei). Let h:D1n→D2n and k:D1n→D2n be two diffeomorphisms (either both orientation preserving or reversing). The plumbing of D(E1) and D(E2) at x1 and x2 is defined to be the quotient space P=D(E1)∪fD(E2) where f:D1n×D1n→D2n×D2n is defined by f(x,y)=(k(y),h(x)). The smooth structure on the quotient is defined by "straightening the angles".

Plumbing according to a tree

If the base manifold is an n-sphere Sn, then by iterating this procedure over several vector bundles over Sn one can plumb them together according to a tree§8. If T is a tree, we assign to each vertex a vector bundle ξ over Sn and we plumb the corresponding disk bundles together if two vertices are connected by an edge. One has to be careful that neighbourhoods in the total spaces do not overlap.

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