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Subset

Set whose elements all belong to another set

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When quantified, A⊆B is represented as ∀x(x∈A⇒x∈B).

One can prove the statement A⊆B by applying a proof technique known as the element argument:

Let sets A and B be given. To prove that A⊆B,

  1. suppose that a is a particular but arbitrarily chosen element of A
  2. show that a is an element of B.

The validity of this technique can be seen as a consequence of universal generalization: the technique shows (c∈A)⇒(c∈B) for an arbitrarily chosen element c. Universal generalisation then implies ∀x(x∈A⇒x∈B), which is equivalent to A⊆B, as stated above.

Definition

If A and B are sets and every element of A is also an element of B, then:

  • A is a subset of B, denoted by A⊆B, or equivalently,
  • B is a superset of A, denoted by B⊇A.

If A is a subset of B, but A is not equal to B (i.e. there exists at least one element of B which is not an element of A), then:

  • A is a proper (or strict) subset of B, denoted by A⊊B, or equivalently,
  • B is a proper (or strict) superset of A, denoted by B⊋A.

The empty set, written {} or ∅, has no elements, and therefore is vacuously a subset of any set X.

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