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Tolman–Oppenheimer–Volkoff equation

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Through Hydrostatics, Gravitational wave and Newton's law of universal gravitation

dPdr=−Gmr2ρ(1+Pρc2)(1+4πr3Pmc2)(1−2Gmrc2)−1

Here, r is a radial coordinate, and ρ(r) and P(r) are the density and pressure, respectively, of the material at radius r. The quantity m(r), the total mass within r, is discussed below.

The equation is derived by solving the Einstein equations for a general time-invariant, spherically symmetric metric. For a solution to the Tolman–Oppenheimer–Volkoff equation, this metric will take the form

ds2=eνc2dt2−(1−2Gmrc2)−1dr2−r2(dθ2+sin2⁡θdϕ2)

where ν(r) is determined by the constraint

dνdr=−(2P+ρc2)dPdr

When supplemented with an equation of state, F(ρ,P)=0, which relates density to pressure, the Tolman–Oppenheimer–Volkoff equation completely determines the structure of a spherically symmetric body of isotropic material in equilibrium. If terms of order 1/c2 are neglected, the Tolman–Oppenheimer–Volkoff equation becomes the Newtonian hydrostatic equation, used to find the equilibrium structure of a spherically symmetric body of isotropic material when general-relativistic corrections are not important.

If the equation is used to model a bounded sphere of material in a vacuum, the zero-pressure condition P(r)=0 and the condition eν=1−2Gm/c2r should be imposed at the boundary. The second boundary condition is imposed so that the metric at the boundary is continuous with the unique static spherically symmetric solution to the vacuum field equations, the Schwarzschild metric:

ds2=(1−2GMrc2)c2dt2−(1−2GMrc2)−1dr2−r2(dθ2+sin2⁡θdϕ2)

Total mass

m(r) is the total mass contained inside radius r, as measured by the gravitational field felt by a distant observer. It satisfies m(0)=0.

dmdr=4πr2ρ

Here, M is the total mass of the object, again, as measured by the gravitational field felt by a distant observer. If the boundary is at r=R, continuity of the metric and the definition of m(r) require that

M=m(R)=∫0R4πr2ρdr

Computing the mass by integrating the density of the object over its volume, on the other hand, will yield the larger value

M1=∫0R4πr2ρ1−2Gmrc2dr

The difference between these two quantities,

δM=∫0R4πr2ρ(1−11−2Gmrc2)dr

will be the gravitational binding energy of the object divided by c2 and it is negative.

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