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Classical electromagnetism and special relativity

Relationship between relativity and pre-quantum electromagnetism

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Maxwell's equations, when they were first stated in their complete form in 1865, would turn out to be compatible with special relativity. Moreover, the apparent coincidences in which the same effect was observed due to different physical phenomena by two different observers would be shown to be not coincidental in the least by special relativity. In fact, half of Einstein's 1905 first paper on special relativity, "On the Electrodynamics of Moving Bodies", explains how to transform Maxwell's equations.

Transformation of the fields between inertial frames

E and B fields

This equation considers two inertial frames. The primed frame is moving relative to the unprimed frame at velocity v. Fields defined in the primed frame are indicated by primes, and fields defined in the unprimed frame lack primes. The field components parallel to the velocity v are denoted by E∥ and B∥ while the field components perpendicular to v are denoted as E⟂ and B⟂. In these two frames moving at relative velocity v, the E-fields and B-fields are related by:

E∥′=E∥B∥′=B∥E⊥′=γ(E⊥+v×B)B⊥′=γ(B⊥−1c2v×E)

where

γ=def11−v2/c2

is called the Lorentz factor and c is the speed of light in free space. Lorentz factor (γ) is the same in both systems. The inverse transformations are the same except for the substitution v → −v.

An equivalent, alternative expression is:

E′=γ(E+v×B)−(γ−1)(E⋅v^)v^B′=γ(B−v×Ec2)−(γ−1)(B⋅v^)v^

where v^=v‖v‖ is the velocity unit vector. With previous notations, one actually has (E⋅v^)v^=E∥ and (B⋅v^)v^=B∥.

Component by component, for relative motion along the x-axis v = (v, 0, 0), this works out to be the following:

Ex′=ExBx′=BxEy′=γ(Ey−vBz)By′=γ(By+vc2Ez)Ez′=γ(Ez+vBy)Bz′=γ(Bz−vc2Ey).

If one of the fields is zero in one frame of reference, that doesn't necessarily mean it is zero in all other frames of reference. This can be seen by, for instance, making the unprimed electric field zero in the transformation to the primed electric field. In this case, depending on the orientation of the magnetic field, the primed system could see an electric field, even though there is none in the unprimed system.

This does not mean two completely different sets of events are seen in the two frames, but that the same sequence of events is described in two different ways (see § Moving magnet and conductor problem below).

If a particle of charge q moves with velocity u with respect to frame S, then the Lorentz force in frame S is:

F=qE+qu×B

In frame S′, the Lorentz force is:

F′=qE′+qu′×B′

A derivation for the transformation of the Lorentz force for the particular case u = 0 is given here. A more general one can be seen here.

The transformations in this form can be made more compact by introducing the electromagnetic tensor (defined below), which is a covariant tensor.

D and H fields

For the electric displacement D and magnetic field strength H, using the constitutive relations and the result for c2:

D=ϵ0E,B=μ0H,c2=1ϵ0μ0,

gives

D′=γ(D+1c2v×H)+(1−γ)(D⋅v^)v^H′=γ(H−v×D)+(1−γ)(H⋅v^)v^

Analogously for E and B, the D and H form the electromagnetic displacement tensor.

φ and A fields

An alternative simpler transformation of the EM field uses the electromagnetic potentials – the electric potential φ and magnetic potential A:

φ′=γ(φ−vA∥)A∥′=γ(A∥−vφc2)A⊥′=A⊥

where A∥ is the component of A that is parallel to the direction of relative velocity between frames v, and A⟂ is the perpendicular component. These transparently resemble the characteristic form of other Lorentz transformations (like time-position and energy-momentum), while the transformations of E and B above are slightly more complicated. The components can be collected together as:

A′=A−γφc2v+(γ−1)(A⋅v^)v^φ′=γ(φ−A⋅v)

ρ and J fields

Analogously for the charge density ρ and current density J,

J∥′=γ(J∥−vρ)ρ′=γ(ρ−vc2J∥)J⊥′=J⊥

Collecting components together:

J′=J−γρv+(γ−1)(J⋅v^)v^ρ′=γ(ρ−J⋅vc2)

Non-relativistic approximations

For speeds v ≪ c, the relativistic factor γ ≈ 1, which yields:

E′≈E+v×BB′≈B−1c2v×EJ′≈J−ρvρ′≈ρ−1c2J⋅v

so that there is no need to distinguish between the spatial and temporal coordinates in Maxwell's equations.

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