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Spin–orbit interaction

Relativistic interaction in quantum physics

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Through Spin (physics), Electron and Energy level

For atoms, energy level splitting produced by the spin–orbit interaction is usually of the same order in size as the relativistic corrections to the kinetic energy and the zitterbewegung effect. The addition of these three corrections is known as the fine structure. The interaction between the magnetic field created by the electron and the magnetic moment of the nucleus is a slighter correction to the energy levels known as the hyperfine structure.

A similar effect, due to the relationship between angular momentum and the strong nuclear force, occurs for protons and neutrons moving inside the nucleus, leading to a shift in their energy levels in the nuclear shell model. In the field of spintronics, spin–orbit effects for electrons in semiconductors and other materials are explored for technological applications. The spin–orbit interaction is at the origin of magnetocrystalline anisotropy and the spin Hall effect.

The interaction was first introduced by Llewellyn Thomas in 1926.

In atomic energy levels

This section presents a relatively simple and quantitative description of the spin–orbit interaction for an electron bound to a hydrogen-like atom, up to first order in perturbation theory, using some semiclassical electrodynamics and non-relativistic quantum mechanics. This gives results that agree reasonably well with observations.

A rigorous calculation of the same result would use relativistic quantum mechanics, using the Dirac equation, and would include many-body interactions. Achieving an even more precise result would involve calculating small corrections from quantum electrodynamics.

Energy of a magnetic moment

The energy of a magnetic moment in a magnetic field is given by ΔH=−μ⋅B, where μ is the magnetic moment of the particle, and B is the magnetic field it experiences.

Magnetic field

We shall deal with the magnetic field first. Although in the rest frame of the nucleus, there is no magnetic field acting on the electron, there is one in the rest frame of the electron (see classical electromagnetism and special relativity). Ignoring for now that this frame is not inertial, we end up with the equation B=−v×Ec2, where v is the velocity of the electron, and E is the electric field it travels through. Here, in the non-relativistic limit, we assume that the Lorentz factor γ⋍1. Now we know that E is radial, so we can rewrite E=|E|rr. Also we know that the momentum of the electron p=mev. Substituting these and changing the order of the cross product (using the identity A×B=−B×A) gives B=r×pmec2|Er|.

Next, we express the electric field as the gradient of the electric potential E=−∇V. Here we make the central field approximation, that is, that the electrostatic potential is spherically symmetric, so is only a function of radius. This approximation is exact for hydrogen and hydrogen-like systems. Now we can say that |E|=|∂V∂r|=1e∂U(r)∂r,

where U=−eV is the potential energy of the electron in the central field, and e is the elementary charge. Now we remember from classical mechanics that the angular momentum of a particle L=r×p. Putting it all together, we get B=1meec21r∂U(r)∂rL.

At this point, B is a positive number multiplied by L, meaning that the magnetic field is parallel to the orbital angular momentum of the particle, which is itself perpendicular to the particle's velocity.

Spin magnetic moment of the electron

The spin magnetic moment of the electron is μS=−gsμBSℏ, where S is the spin (or intrinsic angular-momentum) vector, μB is the Bohr magneton, and gs=2.0023...≈2 is the electron-spin g-factor. Here μ is a negative constant multiplied by the spin, so the spin magnetic moment is antiparallel to the spin.

The spin–orbit potential consists of two parts. The Larmor part is connected to the interaction of the spin magnetic moment of the electron with the magnetic field of the nucleus in the co-moving frame of the electron. The second contribution is related to Thomas precession.

Larmor interaction energy

The Larmor interaction energy is ΔHL=−μ⋅B.

Substituting in this equation expressions for the spin magnetic moment and the magnetic field, one gets ΔHL=gsμBℏmeec21r∂U(r)∂rL⋅S≈2μBℏmeec21r∂U(r)∂rL⋅S.

Now we have to take into account Thomas precession correction for the electron's curved trajectory.

Thomas interaction energy

In 1926 Llewellyn Thomas relativistically recomputed the doublet separation in the fine structure of the atom. Thomas precession rate ΩT is related to the angular frequency of the orbital motion ω of a spinning particle as follows: ΩT=−ω(γ−1), where γ is the Lorentz factor of the moving particle. The Hamiltonian producing the spin precession ΩT is given by ΔHT=ΩT⋅S.

To the first order in (v/c)2, we obtain ΔHT=−μBℏmeec21r∂U(r)∂rL⋅S.

Total interaction energy

The total spin–orbit potential in an external electrostatic potential takes the form ΔH≡ΔHL+ΔHT=(gs−1)μBℏmeec21r∂U(r)∂rL⋅S≈μBℏmeec21r∂U(r)∂rL⋅S. The net effect of Thomas precession is the reduction of the Larmor interaction energy by factor of about 1/2, which came to be known as the Thomas half.

Evaluating the energy shift

Thanks to all the above approximations, we can now evaluate the detailed energy shift in this model. Note that Lz and Sz are no longer conserved quantities. In particular, we wish to find a new basis that diagonalizes both H0 (the non-perturbed Hamiltonian) and ΔH. To find out what basis this is, we first define the total angular momentum operator J=L+S.

Taking the dot product of this with itself, we get J2=L2+S2+2L⋅S (since L and S commute), and therefore L⋅S=12(J2−L2−S2)

It can be shown that the five operators H0, J2, L2, S2, and Jz all commute with each other and with ΔH. Therefore, the basis we were looking for is the simultaneous eigenbasis of these five operators (i.e., the basis where all five are diagonal). Elements of this basis have the five quantum numbers: n (the "principal quantum number"), j (the "total angular momentum quantum number"), ℓ (the "orbital angular momentum quantum number"), s (the "spin quantum number"), and jz (the "z component of total angular momentum").

To evaluate the energies, we note that ⟨1r3⟩=2a3n3ℓ(ℓ+1)(2ℓ+1) for hydrogenic wavefunctions (here a=ℏ/(Zαmec) is the Bohr radius divided by the nuclear charge Z); and ⟨L⋅S⟩=12(⟨J2⟩−⟨L2⟩−⟨S2⟩)=ℏ22(j(j+1)−ℓ(ℓ+1)−s(s+1)).

Final energy shift

We can now say that ΔE=β2(j(j+1)−ℓ(ℓ+1)−s(s+1)), where the spin-orbit coupling constant is β=β(n,l)=Z4μ04πgsμB21n3a03ℓ(ℓ+1/2)(ℓ+1).

For the exact relativistic result, see the solutions to the Dirac equation for a hydrogen-like atom.

The derivation above calculates the interaction energy in the (momentaneous) rest frame of the electron and in this reference frame there's a magnetic field that's absent in the rest frame of the nucleus.

Another approach is to calculate it in the rest frame of the nucleus, see for example George P. Fisher: Electric Dipole Moment of a Moving Magnetic Dipole (1971). However the rest frame calculation is sometimes avoided, because one has to account for hidden momentum.

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