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Electromagnetic wave equation

Partial differential equation used in physics

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Through Electromagnetic radiation, Vacuum and Homogeneous differential equation

(vph2∇2−∂2∂t2)E=0(vph2∇2−∂2∂t2)B=0

where

vph=1με

is the speed of light (i.e. phase velocity) in a medium with permeability μ, and permittivity ε, and ∇2 is the Laplace operator. In a vacuum, vph = c0 = 299792458 m/s, a fundamental physical constant. The electromagnetic wave equation derives from Maxwell's equations. In most older literature, B is called the magnetic flux density or magnetic induction. The following equations∇⋅E=0∇⋅B=0predicate that any electromagnetic wave must be a transverse wave, where the electric field E and the magnetic field B are both perpendicular to the direction of wave propagation.

The origin of the electromagnetic wave equation

In his 1865 paper titled A Dynamical Theory of the Electromagnetic Field, James Clerk Maxwell utilized the correction to Ampère's circuital law that he had made in part III of his 1861 paper On Physical Lines of Force. In Part VI of his 1864 paper titled Electromagnetic Theory of Light, Maxwell combined displacement current with some of the other equations of electromagnetism and he obtained a wave equation with a speed equal to the speed of light. He commented:

The agreement of the results seems to show that light and magnetism are affections of the same substance, and that light is an electromagnetic disturbance propagated through the field according to electromagnetic laws.

Maxwell's derivation of the electromagnetic wave equation has been replaced in modern physics education by a much less cumbersome method involving combining the corrected version of Ampère's circuital law with Faraday's law of induction.

To obtain the electromagnetic wave equation in a vacuum using the modern method, we begin with the modern 'Heaviside' form of Maxwell's equations. In a vacuum- and charge-free space, these equations are:

∇⋅E=0∇×E=−∂B∂t∇⋅B=0∇×B=μ0ε0∂E∂t

These are the general Maxwell's equations specialized to the case with charge and current both set to zero. Taking the curl of the curl equations gives:

∇×(∇×E)=∇×(−∂B∂t)=−∂∂t(∇×B)=−μ0ε0∂2E∂t2∇×(∇×B)=∇×(μ0ε0∂E∂t)=μ0ε0∂∂t(∇×E)=−μ0ε0∂2B∂t2

We can use the vector identity

∇×(∇×V)=∇(∇⋅V)−∇2V

where V is any vector function of space. And

∇2V=∇⋅(∇V)

where ∇V is a dyadic which when operated on by the divergence operator ∇ ⋅ yields a vector. Since

∇⋅E=0∇⋅B=0

then the first term on the right in the identity vanishes and we obtain the wave equations:

1c02∂2E∂t2−∇2E=01c02∂2B∂t2−∇2B=0

where

c0=1μ0ε0=2.99792458×108m/s

is the speed of light in free space.

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