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Ladyzhenskaya's inequality

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Let Ω be a Lipschitz domain in Rn for n=2 or 3 and let u:Ω→R be a weakly differentiable function that vanishes on the boundary of Ω in the sense of trace (that is, u is a limit in the Sobolev space H1(Ω) of a sequence of smooth functions that are compactly supported in Ω). Then there exists a constant C depending only on Ω such that, in the case n=2:

‖u‖L4≤C‖u‖L21/2‖∇u‖L21/2

and in the case n=3:

‖u‖L4≤C‖u‖L21/4‖∇u‖L23/4

Generalizations

  • Both the two- and three-dimensional versions of Ladyzhenskaya's inequality are special cases of the Gagliardo–Nirenberg interpolation inequality
‖u‖Lp≤C‖u‖Lqα‖u‖H0s1−α,
which holds whenever
p>q≥1,s>n(12−1p), and 1p=αq+(1−α)(12−sn).
Ladyzhenskaya's inequalities are the special cases p=4,q=2,s=1 α=12 when n=2 and α=14 when n=3.


  • A simple modification of the argument used by Ladyzhenskaya in her 1958 paper (see e.g. Constantin & Seregin 2010) yields the following inequality for u:R2→R, valid for all r≥2:
‖u‖L2r≤Cr‖u‖Lr1/2‖∇u‖L21/2.
  • The usual Ladyzhenskaya inequality on Rn,n=2 or 3, can be generalized (see McCormick & al. 2013) to use the weak L2 "norm" of u in place of the usual L2 norm:
‖u‖L4≤{C‖u‖L2,∞1/2‖∇u‖L21/2,n=2,C‖u‖L2,∞1/4‖∇u‖L23/4,n=3.

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