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Semidirect product

Operation in group theory

  • 14 min read
  • 7 chapters

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Through Mathematics, Group (mathematics) and Cartesian product

  • an inner semidirect product is a particular way in which a group can be made up of two subgroups, one of which is a normal subgroup.
  • an outer semidirect product is a way to construct a new group from two given groups by using the Cartesian product as a set and a particular multiplication operation.

As with direct products, there is a natural equivalence between inner and outer semidirect products, and both are commonly referred to simply as semidirect products.

For finite groups, the Schur–Zassenhaus theorem provides a sufficient condition for the existence of a decomposition as a semidirect product (also known as splitting extension).

Inner semidirect product definitions

Given a group G with identity element e, a subgroup H, and a normal subgroup N◃G, the following statements are equivalent:

  • G is the product of subgroups, G = NH, and these subgroups have trivial intersection: N ∩ H = {e}.
  • For every g ∈ G, there are unique n ∈ N and h ∈ H such that g = nh.
  • The composition π ∘ i of the natural embedding i : H → G with the natural projection π : G → G/N induces an isomorphism between H and the quotient group G/N.
  • There exists a homomorphism G → H that is the identity on H and whose kernel is N. In other words, there is a split exact sequence 1→N→G→H→1 of groups (which is also known as a split extension of H by N).

If any of these statements holds (and hence all of them hold, by their equivalence), we say G is the semidirect product of N and H, written G=N⋊H or G=H⋉N. The symbol ⋊ is a combination of ◃ and ×, oriented so that N◃(N⋊H), i.e. so that the semidirect product symbol points towards the normal subgroup. Another way of expressing this is that G splits over N; one also says that G is a semidirect product of H acting on N, or even a semidirect product of H and N (though to avoid ambiguity, it is advisable to specify which is the normal subgroup).

If G=N⋊H, then there is a group homomorphism φ:H→Aut(N) given by φh(n)=hnh−1, and for g=nh,g′=n′h′, we have gg′=nhn′h′=nhn′h−1hh′=nφh(n′)hh′=n∗h∗.

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