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Symplectic vector space

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Through Mathematics, Characteristic (algebra) and Skew-symmetric matrix

A symplectic bilinear form is a mapping ω:V×V→F that is

Bilinear
Linear in each argument separately;
Alternating
ω(v,v)=0 holds for all v∈V; and
Non-degenerate
ω(v,u)=0 for all v∈V implies that u=0.

If the underlying field has characteristic not 2, alternation is equivalent to skew-symmetry. If the characteristic is 2, the skew-symmetry is implied by, but does not imply alternation. In this case every symplectic form is a symmetric form, but not vice versa.

Working in a fixed basis, ω can be represented by a matrix. The conditions above are equivalent to this matrix being skew-symmetric, nonsingular, and hollow (all diagonal entries are zero). This should not be confused with a symplectic matrix, which represents a symplectic transformation of the space. If V is finite-dimensional, then its dimension must necessarily be even since every skew-symmetric, hollow matrix of odd size has determinant zero. Notice that the condition that the matrix be hollow is not redundant if the characteristic of the field is 2. A symplectic form behaves quite differently from a symmetric form, for example, the scalar product on Euclidean vector spaces.

Standard symplectic space

The standard symplectic space is R2n with the symplectic form given by a nonsingular, skew-symmetric matrix. Typically ω is chosen to be the block matrix

ω=[0In−In0]

where In is the n × n identity matrix. In terms of basis vectors (x1, ..., xn, y1, ..., yn):

ω(xi,yj)=−ω(yj,xi)=δij,ω(xi,xj)=ω(yi,yj)=0.

A modified version of the Gram–Schmidt process shows that any finite-dimensional symplectic vector space has a basis such that ω takes this form, often called a Darboux basis or symplectic basis.

Sketch of process:

Start with an arbitrary basis v1,...,vn, and represent the dual of each basis vector by the dual basis: ω(vi,⋅)=∑jω(vi,vj)vj∗. This gives us a n×n matrix with entries ω(vi,vj). Solve for its null space. Now for any (λ1,...,λn) in the null space, we have ∑iω(vi,⋅)=0, so the null space gives us the degenerate subspace V0.

Now arbitrarily pick a complementary W such that V=V0⊕W, and let w1,...,wm be a basis of W. Since ω(w1,⋅)≠0, and ω(w1,w1)=0, WLOG ω(w1,w2)≠0. Now scale w2 so that ω(w1,w2)=1. Then define w′=w−ω(w,w2)w1+ω(w,w1)w2 for each of w=w3,w4,...,wm. Iterate.

Notice that this method applies for symplectic vector space over any field, not just the field of real numbers.

Case of real or complex field:

When the space is over the field of real numbers, then we can modify the modified Gram-Schmidt process as follows: Start the same way. Let w1,...,wm be an orthonormal basis (with respect to the usual inner product on Rn) of W. Since ω(w1,⋅)≠0, and ω(w1,w1)=0, WLOG ω(w1,w2)≠0. Now multiply w2 by a sign, so that ω(w1,w2)≥0. Then define w′=w−ω(w,w2)w1+ω(w,w1)w2 for each of w=w3,w4,...,wm, then scale each w′ so that it has norm one. Iterate.

Similarly, for the field of complex numbers, we may choose a unitary basis. This proves the spectral theory of antisymmetric matrices.

Lagrangian form

There is another way to interpret this standard symplectic form. Since the model space R2n used above carries much canonical structure which might easily lead to misinterpretation, we will use "anonymous" vector spaces instead. Let V be a real vector space of dimension n and V∗ its dual space. Now consider the direct sum W = V ⊕ V∗ of these spaces equipped with the following form:

ω(x⊕η,y⊕ξ)=ξ(x)−η(y).

Now choose any basis (v1, ..., vn) of V and consider its dual basis

(v1∗,…,vn∗).

We can interpret the basis vectors as lying in W if we write xi = (vi, 0) and yi = (0, vi∗). Taken together, these form a complete basis of W,

(x1,…,xn,y1,…,yn).

The form ω defined here can be shown to have the same properties as in the beginning of this section. On the other hand, every symplectic structure is isomorphic to one of the form V ⊕ V∗. The subspace V is not unique, and a choice of subspace V is called a polarization. The subspaces that give such an isomorphism are called Lagrangian subspaces or simply Lagrangians.

Explicitly, given a Lagrangian subspace as defined below, then a choice of basis (x1, ..., xn) defines a dual basis for a complement, by ω(xi, yj) = δij.

Analogy with complex structures

Just as every symplectic structure is isomorphic to one of the form V ⊕ V∗, every complex structure on a vector space is isomorphic to one of the form V ⊕ V. Using these structures, the tangent bundle of an n-manifold, considered as a 2n-manifold, has an almost complex structure, and the cotangent bundle of an n-manifold, considered as a 2n-manifold, has a symplectic structure: T∗(T∗M)p = Tp(M) ⊕ (Tp(M))∗.

The complex analog to a Lagrangian subspace is a real subspace, a subspace whose complexification is the whole space: W = V ⊕ J V. As can be seen from the standard symplectic form above, every symplectic form on R2n is isomorphic to the imaginary part of the standard complex (Hermitian) inner product on Cn (with the convention of the first argument being anti-linear).

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