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Triangular distribution

Probability distribution

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Through Statistics, Probability distribution and Decision-making

Special cases

Mode at a bound

The distribution simplifies when c = a or c = b. For example, if a = 0, b = 1 and c = 1, then the PDF and CDF become:

f(x)=2x,F(x)=x2for 0≤x≤1.

E⁡(X)=23Var⁡(X)=118

Distribution of the absolute difference of two standard uniform variables

This distribution for a = 0, b = 1 and c = 0 is the distribution of X = |X1 − X2|, where X1, X2 are two independent random variables with standard uniform distribution.

f(x)=2−2x for 0≤x<1F(x)=2x−x2 for 0≤x<1E(X)=13Var⁡(X)=118

Symmetric triangular distribution

The symmetric case arises when c = (a + b) / 2. In this case, an alternate form of the distribution function is:

f(x)=(b−c)−|c−x|(b−c)2=2b−a(1−|a+b−2x|b−a)

Distribution of the mean of two standard uniform variables

This distribution for a = 0, b = 1 and c = 0.5—the mode (i.e., the peak) is exactly in the middle of the interval—corresponds to the distribution of the mean of two standard uniform variables, that is, the distribution of X = (X1 + X2) / 2, where X1, X2 are two independent random variables with standard uniform distribution in [0, 1]. It is the case of the Bates distribution for two variables.

f(x)={4xfor 0≤x<124(1−x)for 12≤x≤1

F(x)={2x2for 0≤x<122x2−(2x−1)2for 12≤x≤1

E(X)=12Var⁡(X)=124

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