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Aldol condensation

Type of chemical reaction

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Through Organic chemistry, Carbonyl group and Aldehyde

The overall reaction equation is as follows (where the Rs can be H)

Aldol condensations are important in organic synthesis and biochemistry as ways to form carbon–carbon bonds.

In its usual form, it involves the nucleophilic addition of a ketone enolate to an aldehyde to form a β-hydroxy ketone, or aldol (aldehyde + alcohol), a structural unit found in many naturally occurring molecules and pharmaceuticals.

The term aldol condensation is also commonly used, especially in biochemistry, to refer to just the first (addition) stage of the process—the aldol reaction itself—as catalyzed by aldolases. However, the first step is formally an addition reaction rather than a condensation reaction because it does not involve the loss of a small molecule.

Mechanism

The first part of this reaction is an Aldol reaction, the second part a dehydration—an elimination reaction (Involves removal of a water molecule or an alcohol molecule). Dehydration may be accompanied by decarboxylation when an activated carboxyl group is present. The aldol addition product can be dehydrated via two mechanisms; a strong base like potassium t-butoxide, potassium hydroxide or sodium hydride deprotonates the product to an enolate, which eliminates via the E1cB mechanism, while dehydration in acid proceeds via an E1 reaction mechanism. Depending on the nature of the desired product, the aldol condensation may be carried out under two broad types of conditions: kinetic control or thermodynamic control. Both ketones and aldehydes are suitable for aldol condensation reactions. In the examples below, aldehydes are used.

Base-catalyzed aldol condensation

The mechanism for base-catalyzed aldol condensation can be seen in the image below.

Step 1 begins when a hydroxide ion (strong base) abstracts the highly acidic proton at the α-carbon of the aldehyde. This deprotonation causes the electrons from the C–H bond to shift and create an enolate via an E2-like process. The nucleophilic enolate attacks another instance of free aldehyde in step 2, resulting in the formation of a new C–C bond. In step 3, the negative charge is resolved by abstraction of a proton from water to form the aldol, thus regenerating the base catalyst. In the second part of the reaction, the base abstracts the second remaining proton on the α-carbon in an E1cb-Elimination. In the next step, reformation of the carbonyl eliminates a hydroxide leaving group, regenerating the base catalyst once again, and forming the aldol condensation product (an enone).

Acid-catalyzed aldol condensation

The mechanism for acid-catalyzed aldol condensation can be seen in the image below.

Step 1 involves the activation of the first carbonyl via a proton enhances the electrophilicity of its carbon. Water acts as a base in step 2 to tautomerise this activated carbonyl into an enol, an equilibrium driven to the right by the acidic conditions. This enol is a nucleophile, which attacks an activated carbonyl group in a second molecule in step 3 to afford a protonated β-hydroxycarbonyl, which quickly dissociates its surplus proton in step 4. In step 5, the lone pair on the β-hydroxyl oxygen then accepts a free proton, activating it as a leaving group. Step 6 initiates an E1 reaction, in which water leaves, forming a carbocation. Another water molecule completes the E1 reaction by removing the α-proton, resolving the carbocation and forming a double bond. This finally affords the conjugated enone product.

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