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Étale morphism

Concept in algebraic geometry

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  • 4 chapters

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They satisfy the hypotheses of the implicit function theorem, but because open sets in the Zariski topology are so large, they are not necessarily local isomorphisms. Despite this, étale maps retain many of the properties of local analytic isomorphisms, and are useful in defining the algebraic fundamental group and the étale topology.

The word étale is a French adjective, which means "slack", as in "slack tide", or, figuratively, calm, immobile, something left to settle.

Definition

Let ϕ:R→S be a ring homomorphism. This makes S an R-algebra. Choose a monic polynomial f in R[x] and a polynomial g in R[x] such that the derivative f′ of f is a unit in (R[x]/fR[x])g. We say that ϕ is standard étale if f and g can be chosen so that S is isomorphic as an R-algebra to (R[x]/fR[x])g and ϕ is the canonical map.

Let f:X→Y be a morphism of schemes. We say that f is étale if it has any of the following equivalent properties:

  1. f is flat and unramified.
  2. f is a smooth morphism and unramified.
  3. f is flat, locally of finite presentation, and for every y in Y, the fiber f−1(y) is the disjoint union of points, each of which is the spectrum of a finite separable field extension of the residue field κ(y).
  4. f is flat, locally of finite presentation, and for every y in Y and every algebraic closure k′ of the residue field κ(y), the geometric fiber f−1(y)⊗κ(y)k′ is the disjoint union of points, each of which is isomorphic to Spec k′.
  5. f is a smooth morphism of relative dimension zero.
  6. f is a smooth morphism and a locally quasi-finite morphism.
  7. f is locally of finite presentation and is locally a standard étale morphism, that is,
    For every x in X, let y=f(x). Then there is an open affine neighborhood Spec⁡R of y and an open affine neighborhood Spec⁡S of x such that f(Spec⁡S) is contained in Spec⁡R and such that the ring homomorphism R→S induced by f is standard étale.
  8. f is locally of finite presentation and is formally étale.
  9. f is locally of finite presentation and is formally étale for maps from local rings, that is:
    Let A be a local ring and J be an ideal of A such that J2=0. Set Z=Spec⁡A and Z0=Spec⁡A/J, and let i:Z0→Z be the canonical closed immersion. Let z denote the closed point of Z0. Let h:Z→Y and g0:Z0→X be morphisms such that f(g0(z))=h(i(z)). Then there exists a unique Y-morphism g:Z→X such that gi=g0.

Assume that Y is locally noetherian and f is locally of finite type. For x in X, let y=f(x) and let O^Y,y→O^X,x be the induced map on completed local rings. Then the following are equivalent:

  1. f is étale.
  2. For every x in X, the induced map on completed local rings is formally étale for the adic topology.
  3. For every x in X, O^X,x is a free O^Y,y-module and the fiber O^X,x/myO^X,x is a field which is a finite separable field extension of the residue field κ(y). (Here my is the maximal ideal of O^Y,y.)
  4. f is formally étale for maps of local rings with the following additional properties. The local ring A may be assumed Artinian. If m is the maximal ideal of A, then J may be assumed to satisfy mJ=0. Finally, the morphism on residue fields κ(y)→A/m may be assumed to be an isomorphism.

If in addition all the maps on residue fields κ(y)→κ(x) are isomorphisms, or if κ(y) is separably closed, then f is étale if and only if for every x in X, the induced map on completed local rings is an isomorphism.

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