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Maximum modulus principle

Mathematical theorem in complex analysis

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  • 4 chapters

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Through Mathematics, Absolute value and Maximum and minimum

In other words, either f is locally a constant function, or, for any point z0 inside the domain of f there exist other points arbitrarily close to z0 at which |f| takes larger values.

Formal statement

Let f be a holomorphic function on some bounded and connected open subset D of the complex plane C and taking complex values. If z0 is a point in D such that

|f(z0)|≥|f(z)|

for all z in some neighborhood of z0, then f is constant on D.

This statement can be viewed as a special case of the open mapping theorem, which states that a nonconstant holomorphic function maps open sets to open sets: If |f| attains a local maximum at z, then the image of a sufficiently small open neighborhood of z cannot be open, so f is constant.

Suppose that D is a bounded nonempty connected open subset of C. Let D¯ be the closure of D. Suppose that f:D¯→C is a continuous function that is holomorphic on D. Then |f(z)| attains a maximum at some point of the boundary of D.

This follows from the first version as follows. Since D¯ is compact and nonempty, the continuous function |f(z)| attains a maximum at some point z0 of D¯. If z0 is not on the boundary, then the maximum modulus principle implies that f is constant, so |f(z)| also attains the same maximum at any point of the boundary.

Minimum modulus principle

For a holomorphic function f on a connected open set D of C, if z0 is a point in D such that

0<|f(z0)|≤|f(z)|

for all z in some neighborhood of z0, then f is constant on D.

Proof: Apply the maximum modulus principle to 1/f.

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