Lably
Skip to content

Ordinal arithmetic

  • 19 min read
  • 9 chapters

Related on Lably

Through Mathematics, Set theory and Addition

Addition

The sum of two well-ordered sets S and T is the ordinal representing the variant of lexicographical order with least significant position first, on the union of the Cartesian products S × {0} and T × {1}. This way, every element of S is smaller than every element of T, comparisons within S keep the order they already have, and likewise for comparisons within T.

The definition of addition α + β can also be given by transfinite recursion on β. When the right addend β = 0, ordinary addition gives α + 0 = α for any α. For β > 0, the value of α + β is the smallest ordinal strictly greater than the sum of α and δ for all δ < β. Writing the successor and limit ordinals cases separately:

  • α + 0 = α
  • α + S(β) = S(α + β), where S denotes the successor function.
  • α+β=⋃δ<β(α+δ) when β is a limit ordinal.

Ordinal addition on the natural numbers is the same as standard addition. The first transfinite ordinal is ω, the set of all natural numbers, followed by ω + 1, ω + 2, etc. The ordinal ω + ω is obtained by two copies of the natural numbers ordered in the usual fashion and the second copy completely to the right of the first. Writing 0' < 1' < 2' < ... for the second copy, ω + ω looks like

0 < 1 < 2 < 3 < ... < 0' < 1' < 2' < ...

This is different from ω because in ω only 0 does not have a direct predecessor while in ω + ω the two elements 0 and 0' do not have direct predecessors.

Properties

Ordinal addition is, in general, not commutative. For example, 3 + ω = ω since the order relation for 3 + ω is 0 < 1 < 2 < 0' < 1' < 2' < ..., which can be relabeled to ω. In contrast ω + 3 is not equal to ω since the order relation 0 < 1 < 2 < ... < 0' < 1' < 2' has a largest element (namely, 2') and ω does not (ω and ω + 3 are equipotent, but not order isomorphic).

Ordinal addition is still associative; one can see for example that (ω + 4) + ω = ω + (4 + ω) = ω + ω.

Addition is strictly increasing and continuous in the right argument:

α<β⇒γ+α<γ+β

but the analogous relation does not hold for the left argument; instead we only have:

α<β⇒α+γ≤β+γ

Ordinal addition is left-cancellative: if α + β = α + γ, then β = γ. Furthermore, one can define left subtraction for ordinals β ≤ α: there is a unique γ such that α = β + γ. On the other hand, right cancellation does not work:

3+ω=0+ω=ω but 3≠0

Nor does right subtraction, even when β ≤ α: for example, there does not exist any γ such that γ + 42 = ω.

If the ordinals less than α are closed under addition and contain 0, then α is occasionally called a γ-number (see additively indecomposable ordinal). These are exactly the ordinals of the form ωβ.

Sign in to keep reading

8 more chapters are free with a Lably account.

More in Foundations