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Complete measure

Measure space in mathematics

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  • 4 chapters

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Through Mathematics, Measure (mathematics) and Subset

S⊆N∈Σ and μ(N)=0⇒S∈Σ.

Motivation

The need to consider questions of completeness can be illustrated by considering the problem of product spaces.

Suppose that we have already constructed Lebesgue measure on the real line: denote this measure space by (R,B,λ). We now wish to construct some two-dimensional Lebesgue measure λ2 on the plane R2 as a product measure. Naively, we would take the 𝜎-algebra on R2 to be B⊗B, the smallest 𝜎-algebra containing all measurable "rectangles" A1×A2 for A1,A2∈B.

While this approach does define a measure space, it has a flaw. Since every singleton set has one-dimensional Lebesgue measure zero, λ2({0}×A)≤λ({0})=0 for any subset A of R. However, suppose that A is a non-measurable subset of the real line, such as the Vitali set. Then the λ2-measure of {0}×A is not defined but {0}×A⊆{0}×R, and this larger set does have λ2-measure zero. So this "two-dimensional Lebesgue measure" as just defined is not complete, and some kind of completion procedure is required.

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